Question

Balance the following chemical equation ___Ti3N+___MgO—>___Mg3N2+___Ti2O

Answer 1

To balance the chemical equation \( \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \), follow these steps:

1. **Write down the unbalanced equation**:
\[
\text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O}
\]

2. **Count the number of each type of atom on both sides**:
- Reactants:
- Ti: 3
- N: 1
- Mg: 1
- O: 1
- Products:
- Ti: 2
- N: 2
- Mg: 3
- O: 1

3. **Start balancing the most complex compound or the element that appears in the smallest quantity**:
- Start with nitrogen (N). There is 1 N on the left and 2 N on the right. Therefore, place a coefficient of 2 in front of \(\text{Ti}_3\text{N}\) on the left:
\[
2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O}
\]

4. **Update atom counts**:
- Reactants:
- Ti: 6 (from \(2 \times \text{Ti}_3\text{N}\))
- N: 2 (from \(2 \times \text{Ti}_3\text{N}\))
- Mg: 1
- O: 1
- Products:
- Ti: 2
- N: 2
- Mg: 3
- O: 1

5. **Now balance titanium (Ti)**: There are 6 Ti on the left and 2 Ti on the right. Place a coefficient of 3 in front of \(\text{Ti}_2\text{O}\):
\[
2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}
\]

6. **Update atom counts**:
- Reactants:
- Ti: 6
- N: 2
- Mg: 1
- O: 1
- Products:
- Ti: 6 (from \(3 \times \text{Ti}_2\text{O}\))
- N: 2
- Mg: 3
- O: 3 (from \(3 \times \text{Ti}_2\text{O}\))

7. **Finally, balance magnesium (Mg)**: There are 3 Mg on the right, so place a coefficient of 3 in front of \(\text{MgO}\):
\[
2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}
\]

8. **Final check of atom counts**:
- Reactants:
- Ti: 6
- N: 2
- Mg: 3
- O: 3
- Products:
- Ti: 6
- N: 2
- Mg: 3
- O: 3

Since both sides are balanced, the final balanced equation is:
\[
\boxed{2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}}
\]