Question
balance ___Ti3n + ____ MgO → _____ Mg3N2 + ____ Ti2O
Answers
GPT-4o mini
To balance the chemical equation \( \_\_ \text{Ti}_3\text{N} + \_\_ \text{MgO} \rightarrow \_\_ \text{Mg}_3\text{N}_2 + \_\_ \text{Ti}_2\text{O} \), we will follow the steps to ensure that we have the same number of each type of atom on both sides of the equation.
**Step 1: List the number of each type of atom.**
On the left side:
- Titanium (Ti): 3 (from \(\text{Ti}_3\text{N}\))
- Nitrogen (N): 1 (from \(\text{Ti}_3\text{N}\))
- Magnesium (Mg): 1 (from \(\text{MgO}\))
- Oxygen (O): 1 (from \(\text{MgO}\))
On the right side:
- Magnesium (Mg): 3 (from \(\text{Mg}_3\text{N}_2\))
- Nitrogen (N): 2 (from \(\text{Mg}_3\text{N}_2\))
- Titanium (Ti): 2 (from \(\text{Ti}_2\text{O}\))
- Oxygen (O): 2 (from \(\text{Ti}_2\text{O}\))
**Step 2: Balance Nitrogen and Magnesium.**
Since there are 2 nitrogen atoms in \(\text{Mg}_3\text{N}_2\), we need 2 \(\text{Ti}_3\text{N}\):
\[
2 \text{Ti}_3\text{N} \rightarrow 4 \text{N}
\]
We also need 3 Mg from \(\text{Mg}_3\text{N}_2\), thus we need 3 \(\text{MgO}\):
\[
3 \text{MgO} \rightarrow 3\text{Mg}
\]
**Step 3: Balance Titanium.**
Since we have 6 Ti from \(2 \text{Ti}_3\text{N}\), we need:
\[
3 \text{Ti}_2\text{O}
\]
**Step 4: Write the balanced equation.**
Putting it all together, we need:
\[
2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O}
\]
**Final Balanced Equation:**
\[
2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O}
\]
So the coefficients are:
- \(2\), \(6\), \(3\), and \(4\) respectively.
**Step 1: List the number of each type of atom.**
On the left side:
- Titanium (Ti): 3 (from \(\text{Ti}_3\text{N}\))
- Nitrogen (N): 1 (from \(\text{Ti}_3\text{N}\))
- Magnesium (Mg): 1 (from \(\text{MgO}\))
- Oxygen (O): 1 (from \(\text{MgO}\))
On the right side:
- Magnesium (Mg): 3 (from \(\text{Mg}_3\text{N}_2\))
- Nitrogen (N): 2 (from \(\text{Mg}_3\text{N}_2\))
- Titanium (Ti): 2 (from \(\text{Ti}_2\text{O}\))
- Oxygen (O): 2 (from \(\text{Ti}_2\text{O}\))
**Step 2: Balance Nitrogen and Magnesium.**
Since there are 2 nitrogen atoms in \(\text{Mg}_3\text{N}_2\), we need 2 \(\text{Ti}_3\text{N}\):
\[
2 \text{Ti}_3\text{N} \rightarrow 4 \text{N}
\]
We also need 3 Mg from \(\text{Mg}_3\text{N}_2\), thus we need 3 \(\text{MgO}\):
\[
3 \text{MgO} \rightarrow 3\text{Mg}
\]
**Step 3: Balance Titanium.**
Since we have 6 Ti from \(2 \text{Ti}_3\text{N}\), we need:
\[
3 \text{Ti}_2\text{O}
\]
**Step 4: Write the balanced equation.**
Putting it all together, we need:
\[
2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O}
\]
**Final Balanced Equation:**
\[
2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O}
\]
So the coefficients are:
- \(2\), \(6\), \(3\), and \(4\) respectively.