Question
                Solve the following equation for x Express your answer in the simplest form
7(6x - 2) = 7(6x - 2)
The equation has
A: no solution
B: Infinitely many solutions
C: one solution ____
            
        7(6x - 2) = 7(6x - 2)
The equation has
A: no solution
B: Infinitely many solutions
C: one solution ____
Answers
                    Answer
            
    Solve the following equation for x Express your answer in the simplest form
-4(6x-8)=24x+32
The equation has
A: no solution
B: Infinitely many solutions
C: one solution ____
    
-4(6x-8)=24x+32
The equation has
A: no solution
B: Infinitely many solutions
C: one solution ____
                    Answered by
            GPT-4o mini
            
    To solve the equation \( 7(6x - 2) = 7(6x - 2) \), we can first notice that both sides of the equation are identical. 
This means that for any value of \( x \), the left side will always equal the right side. Thus, this equation is true for every value of \( x \).
Therefore, the equation has:
**B: Infinitely many solutions.**
    
This means that for any value of \( x \), the left side will always equal the right side. Thus, this equation is true for every value of \( x \).
Therefore, the equation has:
**B: Infinitely many solutions.**
                    Answered by
            GPT-4o mini
            
    Let's solve the equation step by step:
Given:
\[
-4(6x - 8) = 24x + 32
\]
First, distribute \(-4\) on the left side:
\[
-24x + 32 = 24x + 32
\]
Next, to isolate \(x\), let's move all terms involving \(x\) to one side and the constant terms to the other side. Adding \(24x\) to both sides:
\[
32 = 24x + 24x + 32
\]
This simplifies to:
\[
32 = 48x + 32
\]
Now, subtract \(32\) from both sides:
\[
0 = 48x
\]
Dividing both sides by \(48\):
\[
x = 0
\]
So, the solution is \( x = 0 \).
Since we found a specific solution, the answer is:
**C: one solution \(\, x = 0\).**
    
Given:
\[
-4(6x - 8) = 24x + 32
\]
First, distribute \(-4\) on the left side:
\[
-24x + 32 = 24x + 32
\]
Next, to isolate \(x\), let's move all terms involving \(x\) to one side and the constant terms to the other side. Adding \(24x\) to both sides:
\[
32 = 24x + 24x + 32
\]
This simplifies to:
\[
32 = 48x + 32
\]
Now, subtract \(32\) from both sides:
\[
0 = 48x
\]
Dividing both sides by \(48\):
\[
x = 0
\]
So, the solution is \( x = 0 \).
Since we found a specific solution, the answer is:
**C: one solution \(\, x = 0\).**
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