1) ctgx+cosx=1+ctgx*cosx

2) sin^4x+cos^4x=1/2

3) (sinx-cosx)^2=sin2x

4) sin^4x-cos^4x=7/2(sinxcosx)

5) sin^2x-sinxcosx+cosx-sinx=0

2 answers

How about you try first and post your results.
2) sin^4x+cos^4x=1/2
sin^2x*sin^2x+cos^4x=1/2
(1-cos^2x)(1-cos^2x)+cos^4x=1/2
1-cos^2x-cos^2x+2cos^4x=1/2
2cos^4x-2cos^2x+1=1/2
2cos^4x-2cos^2x+1/2=0
x=pi/4+2kpi x2=7pi/4+2kpi
Similar Questions
  1. Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
    1. answers icon 1 answer
  2. Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
    1. answers icon 1 answer
  3. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    1. answers icon 3 answers
more similar questions