Asked by Anonymous
beth is two years older than julio.Gerald is twice as old as beth.debra is twice as old as gerald.the sum of theIr ages is 38.how old is beth?
Answers
Answered by
MathMate
B=age of Beth,
J=age of Julio
G=age of Gerald
D=age of Debra
Equations, expressed in terms of J
B=J+2
G=2B=2(J+2)=2J+4
D=2G=2(2J+4)=4J+8
Finally
J+B+G+D=38 and substitute above values:
J+(J+2)+(2J+4)+4J+8=38
8J+14=38
J=3
Backsubstitute J in the above equations to get the ages of Beth, Gerald and Debra.
J=age of Julio
G=age of Gerald
D=age of Debra
Equations, expressed in terms of J
B=J+2
G=2B=2(J+2)=2J+4
D=2G=2(2J+4)=4J+8
Finally
J+B+G+D=38 and substitute above values:
J+(J+2)+(2J+4)+4J+8=38
8J+14=38
J=3
Backsubstitute J in the above equations to get the ages of Beth, Gerald and Debra.
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