Question

For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
Responses

6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48

8(x − 6) = 48
8 left parenthesis x minus 6 right parenthesis equals 48

6x − 8 = 48
6 x minus 8 equals 48

6(x + 8) = 48

Answer 1

To determine which equation fits the order of steps "to first divide both sides by 6 and then to add 8 to both sides," we can analyze each option.

1. **For the equation 6(x − 8) = 48**:
- Dividing both sides by 6: \( x - 8 = 8 \)
- Adding 8 to both sides: \( x = 16 \)

2. **For the equation 8(x − 6) = 48**:
- Dividing both sides by 8: \( x - 6 = 6 \)
- Adding 6 to both sides: \( x = 12 \) (This does not match as we divide by 8).

3. **For the equation 6x − 8 = 48**:
- Dividing both sides by 6: \( x - \frac{8}{6} = 8 \) (This is incorrect for dividing by 6 first).
- Adding 8 to both sides would not follow the definition either.

4. **For the equation 6(x + 8) = 48**:
- Dividing both sides by 6: \( x + 8 = 8 \)
- Adding 8 to both sides: \( x = 0 \) (same reasoning as above).

The correct choice is **6(x − 8) = 48**, as this equation allows you to first divide both sides by 6 and then add 8 to both sides, the required steps.