Question
A sample of helium behaves as an ideal gas as it is heated at constant pressure from 273 K to 373 K. If 15.0 J of work is done by the gas during this process, what is the mass of helium present?
I am not sure what equations to use for this problem....
I am not sure what equations to use for this problem....
Answers
PV=nRT
p dV + V dp = n R dT
p is constant here so
p dV = n R dT
work = integral p dV = nR dT
p(V2-V1) = n R (T2-T1)
so 15 = n R (T2-T1)
p dV + V dp = n R dT
p is constant here so
p dV = n R dT
work = integral p dV = nR dT
p(V2-V1) = n R (T2-T1)
so 15 = n R (T2-T1)
doesnt that give me an answer in moles? ...is there a way to convert moles to mg?
so i got the answer to be .01804 moles
and i know one mole of helium is 4.03 g
do i just multiply the two together? and then divide by 10000 to convert g to mg?
and i know one mole of helium is 4.03 g
do i just multiply the two together? and then divide by 10000 to convert g to mg?
never mind. I made a silly error.
i got .01804 moles...multiplied that times 4.03grams and then multiplied that times 1000 and got 72.7mg.
got it! thanks so much!
i got .01804 moles...multiplied that times 4.03grams and then multiplied that times 1000 and got 72.7mg.
got it! thanks so much!
what are we solving for in this equation?? 15 = n R (T2-T1)
we know n, we know R, we know t1 and t2...so what do we solve for?
we know n, we know R, we know t1 and t2...so what do we solve for?
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