Asked by Anonymous
1.50 mol sample of helium at a certain pressure and temperature has a volume of 31.4 L. a second sample of helium at the same temperature and pressure has a volume of 42.4 L. Therefore the second sample contains how many moles of helium?
Answers
Answered by
DrBob222
You can reason through it this way
PV = nRT. Since P, R and T are constant, then V = n*constant which I'll call k and
V = nk.
Evaluate k by 31.4 = 1.5k and k = 31.4/1.4 = 20.93.
Then V = nk
41.4 = n*20.93 and
n = 41.4/20.93 - 2.03 mols.
OR you can reason that a higher volume at the same T and P must have more moles by the fraction
1.5 x (41.4/31.4) = ?
PV = nRT. Since P, R and T are constant, then V = n*constant which I'll call k and
V = nk.
Evaluate k by 31.4 = 1.5k and k = 31.4/1.4 = 20.93.
Then V = nk
41.4 = n*20.93 and
n = 41.4/20.93 - 2.03 mols.
OR you can reason that a higher volume at the same T and P must have more moles by the fraction
1.5 x (41.4/31.4) = ?
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