To determine which graph accurately displays the situation described, we'll need to analyze the function \( a(t) = 1000(1.09)^t \) over the relevant period, which is 10 years for Callie's scholarship.
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Function Analysis: The amount in the account after \( t \) years is modeled by \( a(t) = 1000(1.09)^t \). This is an exponential growth function.
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Calculate Amount after 10 Years: We need to find \( a(10) \): \[ a(10) = 1000(1.09)^{10} \]
Using a calculator: \[ (1.09)^{10} \approx 2.3674 \] Therefore: \[ a(10) \approx 1000 \times 2.3674 \approx 2367.40 \]
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Behavior of the Function: Since this is an exponential function with a positive growth rate, \( a(t) \) continuously increases as \( t \) increases.
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Graph Selection: Now we examine the options based on the expected behavior of \( a(t) \):
- The graph should show an increasing curve because the amount grows over time.
- At \( t = 10 \), the value should be around 2367.40, thus well within the range of 0 to 3,500 on the y-axis.
Evaluating the Options:
- First Graph: Increasing curve, x-axis from 0 to 14, y-axis from 0 to 3,500 - This graph is suitable.
- Second Graph: Increasing curve, x-axis from 0 to 5, y-axis from 0 to 2000 - This graph is insufficient since it doesn't reach up to 10 years and limits the range.
- Third Graph: Decreasing curve - Not applicable since the function is increasing.
- Fourth Graph: Increasing curve, x-axis from 0 to 10, y-axis from 0 to 2000 - This might show part of the growth, but it doesn't cover the upper bound around 2367.40 adequately.
Conclusion:
The first graph accurately displays the situation because it shows an increasing curve and accommodates the values we expect for \( a(t) \) after 10 years, ranging correctly to 3,500 on the y-axis.