Callie entered an art contest in second grade and won a $1,000 scholarship. The money was invested in an account paying a 9% interest rate compounded annually. The situation can be modeled by the equation a(t)=1,000(1.09)t, where a is the amount in the account after t years. If Callie uses the scholarship 10 years later, determine which graph accurately displays the situation.(1 point)

what would the graph look like?

1 answer

To visualize the situation described, we can analyze the function \( a(t) = 1,000(1.09)^t \). This function represents exponential growth due to the annual compounding interest at a rate of 9%.

Key Characteristics of the Graph:

  1. Initial Value: When \( t = 0 \) (the time the scholarship was awarded), the amount \( a(0) \) is: \[ a(0) = 1,000(1.09)^0 = 1,000 \] This means the graph starts at the point (0, 1000).

  2. Growth Rate: The function grows exponentially, so the graph will curve upward as \( t \) increases.

  3. Value after 10 Years: To find out how much Callie will have after 10 years, we can calculate \( a(10) \): \[ a(10) = 1,000(1.09)^{10} \] Calculating \( (1.09)^{10} \) gives approximately \( 2.3674 \) (using a calculator). Thus, \[ a(10) \approx 1,000 \times 2.3674 = 2,367.4 \]

  4. Shape of the Graph: The graph will be a smooth curve that rises steeply after several years, characteristic of exponential functions.

Appearance of the Graph:

  • The x-axis will represent time (in years).
  • The y-axis will represent the amount in the account.
  • The graph will start at (0, 1000) and will rise sharply upwards, crossing points like (10, 2367.4) and even higher values as time progresses.

Conclusion:

The correct graph will start at (0, 1000) and will follow a steeply rising curve as time increases. It will not be a straight line but rather an upward-curving line reflecting the exponential growth nature of the compounded interest. If you’re looking at a set of graphs, choose the one that has this characteristic upward exponential growth starting from that initial amount.