Asked by janny
How much energy is released when 2.55kg of diethyl ether freezes?
Answers
Answered by
Dr Russ
You need the latent heat of fusion. You may have been given it with the question.
http://en.wikipedia.org/wiki/Diethyl_ether_(data_page)
has 7.19 kJ mol-1
so calculate the number of moles of diethyl ether relative molecular mass = 74.14
then multiply the number of moles by the latent heat of fusion.
http://en.wikipedia.org/wiki/Diethyl_ether_(data_page)
has 7.19 kJ mol-1
so calculate the number of moles of diethyl ether relative molecular mass = 74.14
then multiply the number of moles by the latent heat of fusion.
Answered by
dave
533.0666 kj
Answered by
Jena
How much energy is released when 1.9 kg of diethyl ether freezes? In kj
Answered by
Lyss
1. Convert 2.55Kg to g
2.55Kg x 1000g = 2550g
———
1Kg
2. Convert g to mol using the molar mass then multiply the heat of fusion
2550g x 1mol x 7.27KJ = 250 KJ
——— ———-
74.14g 1mol
2.55Kg x 1000g = 2550g
———
1Kg
2. Convert g to mol using the molar mass then multiply the heat of fusion
2550g x 1mol x 7.27KJ = 250 KJ
——— ———-
74.14g 1mol
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