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Use technology to find points and then graph the function y, equals, 2, start superscript, x, minus, 2, end superscript, minus,...Question
Use technology to find points and then graph the function y, equals, 2, start superscript, x, minus, 4, end superscript, minus, 1, commay=2
x−4
−1, following the instructions below.
Equation of asymptote:
y, equalsy=
Plot at least four points with integer coordinates that fit on the axes below
x−4
−1, following the instructions below.
Equation of asymptote:
y, equalsy=
Plot at least four points with integer coordinates that fit on the axes below
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Answered by
GPT-4o mini
To analyze the function \( y = 2^{(x - 4)} - 1 \) and find the points to plot, we can first identify the characteristics of this function and its asymptote.
### Step 1: Asymptote
The function \( y = 2^{(x - 4)} - 1 \) approaches the line \( y = -1 \) as \( x \) approaches negative infinity. Therefore, the equation of the asymptote is:
\[ y = -1 \]
### Step 2: Finding Points
To plot the function, we can calculate the \( y \) values for various integer \( x \) values. We'll choose a range of \( x \) values to see how the function behaves.
Let's evaluate the function at \( x = 0, 1, 2, 3, 4, 5, 6, 7 \):
- For \( x = 0 \):
\[
y = 2^{(0 - 4)} - 1 = 2^{-4} - 1 = \frac{1}{16} - 1 = \frac{1 - 16}{16} = -\frac{15}{16} \approx -0.9375
\]
- For \( x = 1 \):
\[
y = 2^{(1 - 4)} - 1 = 2^{-3} - 1 = \frac{1}{8} - 1 = \frac{1 - 8}{8} = -\frac{7}{8} = -0.875
\]
- For \( x = 2 \):
\[
y = 2^{(2 - 4)} - 1 = 2^{-2} - 1 = \frac{1}{4} - 1 = \frac{1 - 4}{4} = -\frac{3}{4} = -0.75
\]
- For \( x = 3 \):
\[
y = 2^{(3 - 4)} - 1 = 2^{-1} - 1 = \frac{1}{2} - 1 = \frac{1 - 2}{2} = -\frac{1}{2} = -0.5
\]
- For \( x = 4 \):
\[
y = 2^{(4 - 4)} - 1 = 2^{0} - 1 = 1 - 1 = 0
\]
- For \( x = 5 \):
\[
y = 2^{(5 - 4)} - 1 = 2^{1} - 1 = 2 - 1 = 1
\]
- For \( x = 6 \):
\[
y = 2^{(6 - 4)} - 1 = 2^{2} - 1 = 4 - 1 = 3
\]
- For \( x = 7 \):
\[
y = 2^{(7 - 4)} - 1 = 2^{3} - 1 = 8 - 1 = 7
\]
### Step 3: Integer Points
Let's focus on the integer coordinate points we found:
- \( (4, 0) \)
- \( (5, 1) \)
- \( (6, 3) \)
- \( (7, 7) \)
### Results
Here are the integer coordinates we can plot:
1. \( (4, 0) \)
2. \( (5, 1) \)
3. \( (6, 3) \)
4. \( (7, 7) \)
### Graphing the Function
On a coordinate plane, we can mark these points. The asymptote \( y = -1 \) will also be represented as a dashed horizontal line across the graph at \( y = -1 \).
Here's a simple representation of the function:
- The curve rises steeply after \( x = 4 \).
- It approaches the asymptote (horizontal line at \( y = -1 \)) for smaller values of \( x \).
### Final Summary
- **Equation of Asymptote:** \( y = -1 \)
- **Integer Points to Plot:**
- \( (4, 0) \)
- \( (5, 1) \)
- \( (6, 3) \)
- \( (7, 7) \)
You can plot these points and sketch the curve for a complete view of the function behavior!
### Step 1: Asymptote
The function \( y = 2^{(x - 4)} - 1 \) approaches the line \( y = -1 \) as \( x \) approaches negative infinity. Therefore, the equation of the asymptote is:
\[ y = -1 \]
### Step 2: Finding Points
To plot the function, we can calculate the \( y \) values for various integer \( x \) values. We'll choose a range of \( x \) values to see how the function behaves.
Let's evaluate the function at \( x = 0, 1, 2, 3, 4, 5, 6, 7 \):
- For \( x = 0 \):
\[
y = 2^{(0 - 4)} - 1 = 2^{-4} - 1 = \frac{1}{16} - 1 = \frac{1 - 16}{16} = -\frac{15}{16} \approx -0.9375
\]
- For \( x = 1 \):
\[
y = 2^{(1 - 4)} - 1 = 2^{-3} - 1 = \frac{1}{8} - 1 = \frac{1 - 8}{8} = -\frac{7}{8} = -0.875
\]
- For \( x = 2 \):
\[
y = 2^{(2 - 4)} - 1 = 2^{-2} - 1 = \frac{1}{4} - 1 = \frac{1 - 4}{4} = -\frac{3}{4} = -0.75
\]
- For \( x = 3 \):
\[
y = 2^{(3 - 4)} - 1 = 2^{-1} - 1 = \frac{1}{2} - 1 = \frac{1 - 2}{2} = -\frac{1}{2} = -0.5
\]
- For \( x = 4 \):
\[
y = 2^{(4 - 4)} - 1 = 2^{0} - 1 = 1 - 1 = 0
\]
- For \( x = 5 \):
\[
y = 2^{(5 - 4)} - 1 = 2^{1} - 1 = 2 - 1 = 1
\]
- For \( x = 6 \):
\[
y = 2^{(6 - 4)} - 1 = 2^{2} - 1 = 4 - 1 = 3
\]
- For \( x = 7 \):
\[
y = 2^{(7 - 4)} - 1 = 2^{3} - 1 = 8 - 1 = 7
\]
### Step 3: Integer Points
Let's focus on the integer coordinate points we found:
- \( (4, 0) \)
- \( (5, 1) \)
- \( (6, 3) \)
- \( (7, 7) \)
### Results
Here are the integer coordinates we can plot:
1. \( (4, 0) \)
2. \( (5, 1) \)
3. \( (6, 3) \)
4. \( (7, 7) \)
### Graphing the Function
On a coordinate plane, we can mark these points. The asymptote \( y = -1 \) will also be represented as a dashed horizontal line across the graph at \( y = -1 \).
Here's a simple representation of the function:
- The curve rises steeply after \( x = 4 \).
- It approaches the asymptote (horizontal line at \( y = -1 \)) for smaller values of \( x \).
### Final Summary
- **Equation of Asymptote:** \( y = -1 \)
- **Integer Points to Plot:**
- \( (4, 0) \)
- \( (5, 1) \)
- \( (6, 3) \)
- \( (7, 7) \)
You can plot these points and sketch the curve for a complete view of the function behavior!
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