balance the following chemical equation

Question

2Ag2O>____Ag+____O2

Answer 1

To balance the chemical equation \( 2 \text{Ag}_2\text{O} \rightarrow __ \text{Ag} + __ \text{O}_2 \), follow these steps:

1. Count the number of each type of atom on both sides of the equation.

   • On the left side (reactants), we have:
     • Silver (Ag): \( 2 \times 2 = 4 \) atoms
     • Oxygen (O): \( 2 \) atoms
   • On the right side (products), we currently have:
     • Silver (Ag): \( 0 \) atoms
     • Oxygen (O): \( 0 \) atoms

2. Start by balancing the silver (Ag) atoms.

   • Since there are 4 Ag on the left, place a coefficient of 4 in front of Ag on the right:
     • \( \rightarrow 4 \text{Ag} + __ \text{O}_2 \)

3. Now, balance the oxygen (O) atoms.

   • There are 2 O on the left. Since \( \text{O}_2 \) contains 2 O, you need a coefficient of 1 in front of \( \text{O}_2 \):
     • \( \rightarrow 4 \text{Ag} + 1 \text{O}_2 \)

Putting it all together, the balanced equation is:

\[ 2 \text{Ag}_2\text{O} \rightarrow 4 \text{Ag} + 1 \text{O}_2 \]

So the final answer is:

\[ 2 \text{Ag}_2\text{O} \rightarrow 4 \text{Ag} + 1 \text{O}_2 \]