sin s = 1/4 and s in II, ---> tan s = -1/√15
sin t = -1/2, and t in IV ---> tan t = -1/√3
tan(s+t) = (tans + tant)/(1 - tanstant)
= (-1/√15 - 1/√3)/(1 - 1/√45)
I will let you finish the arithmetic.
How do i set this trig problem up? PLEASE help me.
Find tan (s + t) given that sin s = 1/4, with s in quadrant 2, and sin t = -1/2, with t in quadrant 4.
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