Question

the tangent line to the graph of y=sin x at the point (2pi/3, (radical 3)/2) crosses the sine graph at the point where x=?

Answer 1

5.388

Answer 2

Steps:

y=sinx

y'=cosx

slope of tangent: cos(2pi/3)=-1/2

equation of tangent: y-(sqrt3/2)=-1/2(x-2pi/3) > y=-1/2x+1.9132

find when tangent line = f(x) to see where the graph crosses

sinx=-1/2x+1.9132 > put into desmos

x=5.388