Question
what is 0 in radians sin0=sqrt2/2
I will describe the image
There is a 1 on the x and y
There is a 30 45 and 60 degree angle in it
The top equations are 1/2 and sqrt3/2
The middle ones are sqrt 2/2 and sqrt 2/2
And the bottom ones are sqrt 3/2 and 1/2
I will describe the image
There is a 1 on the x and y
There is a 30 45 and 60 degree angle in it
The top equations are 1/2 and sqrt3/2
The middle ones are sqrt 2/2 and sqrt 2/2
And the bottom ones are sqrt 3/2 and 1/2
Answers
Answered by
GPT-4o mini
Based on your description, it seems that you’re referring to the unit circle and the sine values associated with common angles (30°, 45°, and 60°) in trigonometry.
In the unit circle:
1. \( \sin(0) = 0 \)
2. \( \sin(30^\circ) = \frac{1}{2} \)
3. \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \)
4. \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \)
It looks like there may be some confusion in your question. The sine of 0 radians (or 0 degrees) is indeed 0, not \( \frac{\sqrt{2}}{2} \).
The value \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \) indicates the sine of a 45-degree angle, not 0 degrees.
In summary:
- \( 0 \) radians corresponds to \( 0^\circ \), and \( \sin(0) = 0 \).
- \( \frac{\sqrt{2}}{2} \) corresponds to \( 45^\circ\) (or \( \frac{\pi}{4} \) radians).
If you have any other questions about angles or trigonometric functions, feel free to ask!
In the unit circle:
1. \( \sin(0) = 0 \)
2. \( \sin(30^\circ) = \frac{1}{2} \)
3. \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \)
4. \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \)
It looks like there may be some confusion in your question. The sine of 0 radians (or 0 degrees) is indeed 0, not \( \frac{\sqrt{2}}{2} \).
The value \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \) indicates the sine of a 45-degree angle, not 0 degrees.
In summary:
- \( 0 \) radians corresponds to \( 0^\circ \), and \( \sin(0) = 0 \).
- \( \frac{\sqrt{2}}{2} \) corresponds to \( 45^\circ\) (or \( \frac{\pi}{4} \) radians).
If you have any other questions about angles or trigonometric functions, feel free to ask!