Asked by s
verify sin0/sin0+cos0=tan0/1+tan0
Answers
Answered by
Reiny
I will assume you meant:
sinØ/(sinØ + cosØ) = tanØ/(1 + tanØ
RS = (sinØ/cosØ)/(1 + sinØ/cosØ)
= (sinØ/cosØ)/)( ( cosØ+sinØ)/cosØ)
= (sinØ/cosØ) (cosØ/(cosØ + sinØ ) )
= sinØ/(sinØ + cosØ)
= LS
sinØ/(sinØ + cosØ) = tanØ/(1 + tanØ
RS = (sinØ/cosØ)/(1 + sinØ/cosØ)
= (sinØ/cosØ)/)( ( cosØ+sinØ)/cosØ)
= (sinØ/cosØ) (cosØ/(cosØ + sinØ ) )
= sinØ/(sinØ + cosØ)
= LS
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