Question
Question 24
If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball?
F= ma
a
3.15 m/s2
b
388.9 m/s2
c
315 m/s2
d
2.6 m/s2
e
0.003 m/s2
f
0.32 m/s2
Question 25
The graph below represents the relationship between speed and time for a car moving in a straight line.
What is the acceleration of the car?
a
0.10 m/s2
b
0 m/s2
c
1.0 m/s2
d
10 m/s2
Question 26
Which terms correctly represent a vector quantity and its respective unit?
a
mass - kilogram
b
weight - kilogram
c
speed - meters per second
d
force - Newton
Question 27
Balance the following the chemical equation:
_ Mg + _ F2 → _ MgF2
a
1:1:2
b
1:2:1
c
1:1:1
d
2:1:1
If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball?
F= ma
a
3.15 m/s2
b
388.9 m/s2
c
315 m/s2
d
2.6 m/s2
e
0.003 m/s2
f
0.32 m/s2
Question 25
The graph below represents the relationship between speed and time for a car moving in a straight line.
What is the acceleration of the car?
a
0.10 m/s2
b
0 m/s2
c
1.0 m/s2
d
10 m/s2
Question 26
Which terms correctly represent a vector quantity and its respective unit?
a
mass - kilogram
b
weight - kilogram
c
speed - meters per second
d
force - Newton
Question 27
Balance the following the chemical equation:
_ Mg + _ F2 → _ MgF2
a
1:1:2
b
1:2:1
c
1:1:1
d
2:1:1
Answers
GPT-4o mini
Let's work through each of your questions one by one.
**Question 24:**
To find the acceleration of the soccer ball, you can use Newton's second law of motion, which is given by the equation \( F = ma \).
Here,
- \( F = 0.90 \, \text{N} \)
- \( m = 0.350 \, \text{kg} \)
We need to find \( a \):
\[
a = \frac{F}{m} = \frac{0.90 \, \text{N}}{0.350 \, \text{kg}} \approx 2.57 \, \text{m/s}^2
\]
This is roughly \( 2.6 \, \text{m/s}^2 \).
**Answer: d - 2.6 m/s²**
---
**Question 25:**
Without the graph to visually reference, I will explain how to calculate acceleration.
If the speed is linear (i.e., a straight line), the acceleration can be found by taking the change in speed (Δv) divided by the change in time (Δt).
Assuming you can see from the graph that the change in speed is, say, 10 m/s over 100 seconds, then:
\[
\text{Acceleration} = \frac{\Delta v}{\Delta t} = \frac{10 \, \text{m/s}}{100 \, \text{s}} = 0.1 \, \text{m/s}^2
\]
So, if such is the case:
**Answer: a - 0.10 m/s²**
---
**Question 26:**
Vector quantities are those that have both magnitude and direction. Let's evaluate the options:
- a: mass - kilogram (scalar) - Not a vector
- b: weight - kilogram (not correct, weight is a vector with the unit Newton) - Not a vector
- c: speed - meters per second (scalar) - Not a vector
- d: force - Newton (vector) - Correct
**Answer: d - force - Newton**
---
**Question 27:**
To balance the equation \( \text{Mg} + \text{F}_2 \rightarrow \text{MgF}_2 \):
1 magnesium atom on the left must equal 1 magnesium atom on the right, and 2 fluorine atoms on the right must equal 2 on the left.
Thus:
- _1 Mg + _2 F₂ → _1 MgF₂
So the balanced equation is:
1:2:1
**Answer: b - 1:2:1**
**Question 24:**
To find the acceleration of the soccer ball, you can use Newton's second law of motion, which is given by the equation \( F = ma \).
Here,
- \( F = 0.90 \, \text{N} \)
- \( m = 0.350 \, \text{kg} \)
We need to find \( a \):
\[
a = \frac{F}{m} = \frac{0.90 \, \text{N}}{0.350 \, \text{kg}} \approx 2.57 \, \text{m/s}^2
\]
This is roughly \( 2.6 \, \text{m/s}^2 \).
**Answer: d - 2.6 m/s²**
---
**Question 25:**
Without the graph to visually reference, I will explain how to calculate acceleration.
If the speed is linear (i.e., a straight line), the acceleration can be found by taking the change in speed (Δv) divided by the change in time (Δt).
Assuming you can see from the graph that the change in speed is, say, 10 m/s over 100 seconds, then:
\[
\text{Acceleration} = \frac{\Delta v}{\Delta t} = \frac{10 \, \text{m/s}}{100 \, \text{s}} = 0.1 \, \text{m/s}^2
\]
So, if such is the case:
**Answer: a - 0.10 m/s²**
---
**Question 26:**
Vector quantities are those that have both magnitude and direction. Let's evaluate the options:
- a: mass - kilogram (scalar) - Not a vector
- b: weight - kilogram (not correct, weight is a vector with the unit Newton) - Not a vector
- c: speed - meters per second (scalar) - Not a vector
- d: force - Newton (vector) - Correct
**Answer: d - force - Newton**
---
**Question 27:**
To balance the equation \( \text{Mg} + \text{F}_2 \rightarrow \text{MgF}_2 \):
1 magnesium atom on the left must equal 1 magnesium atom on the right, and 2 fluorine atoms on the right must equal 2 on the left.
Thus:
- _1 Mg + _2 F₂ → _1 MgF₂
So the balanced equation is:
1:2:1
**Answer: b - 1:2:1**