Question

Question 22
If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball?

F= ma

a
3.15 m/s2

b
0.003 m/s2

c
0.32 m/s2

d
2.6 m/s2

e
388.9 m/s2

f
315 m/s2

Answer 1

To find the acceleration of the soccer ball, we can use Newton's second law, which states:

\[ F = m \cdot a \]

Where:
- \( F \) is the force (0.90 N),
- \( m \) is the mass (0.350 kg),
- \( a \) is the acceleration.

We can rearrange this formula to solve for acceleration \( a \):

\[ a = \frac{F}{m} \]

Now, we can plug in the values:

\[ a = \frac{0.90 \, \text{N}}{0.350 \, \text{kg}} \]

Calculating this:

\[ a = \frac{0.90}{0.350} \approx 2.57 \, \text{m/s}^2 \]

Considering rounding, this value aligns closely with option (d) 2.6 m/s². Thus, the correct answer is:

**d. 2.6 m/s²**