Asked by William
can any one explain how to evaluate this improper integral i.e. the function is not continuous at 0 neither at inf
integration of [(e^(-sqrt(t)))/sqrt(t)]dt from 0 to infinity
the integration part is easy but i want only how to evaluate it
thanks
integration of [(e^(-sqrt(t)))/sqrt(t)]dt from 0 to infinity
the integration part is easy but i want only how to evaluate it
thanks
Answers
Answered by
drwls
The indefinite integral is -2 e^(-sqrt(t))
At t = 0, the value of the indefinite integral is -2, and at t = infinity, it approaches zero
Therefore the integral is 0 - (-2) = 2
Integrals to not have to diverge just because the integrand diverges at the endpoints. It all depends upon how fast the functions approach infinity.
At t = 0, the value of the indefinite integral is -2, and at t = infinity, it approaches zero
Therefore the integral is 0 - (-2) = 2
Integrals to not have to diverge just because the integrand diverges at the endpoints. It all depends upon how fast the functions approach infinity.
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