Question

What is the equation in point slope form of the line that passes through the point (−1, −3)
and has a slope of 4?



Responses

y−3=4(x−1)
y minus 3 equals 4 open parenthesis x minus 1 close parenthesis

y+3=4(x+1)
y plus 3 equals 4 open parenthesis x plus 1 close parenthesis

y−1=4(x−3)
y minus 1 equals 4 open parenthesis x minus 3 close parenthesis

y+1=4(x+3)

Answer 1

To write the equation of a line in point-slope form, you can use the formula:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line.

Given:
- The point \( (-1, -3) \) gives us \( x_1 = -1 \) and \( y_1 = -3 \).
- The slope \( m = 4 \).

Substituting these values into the formula:

\[ y - (-3) = 4(x - (-1)) \]
\[ y + 3 = 4(x + 1) \]

Thus, the equation in point-slope form is:

\[ y + 3 = 4(x + 1) \]

So, the correct response is:

**y + 3 = 4(x + 1)**