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Identify the error in the syntax of the following code: def is_year(year): if year % 4 == 0: print('Year is divisible by 4') el...Question
Identify the error in the syntax of the following code:
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else year % 4 != 0:
print('Year is not divisible by 4')
(1 point)
Responses
There should not be a colon after the function definition.
There should not be a colon after the function definition.
The print statements shall be ended with a semi-colon.
The print statements shall be ended with a semi-colon.
You cannot add a conditional statement after the else keyword.
You cannot add a conditional statement after the else keyword.
There should be a double modulus to check for the remainder.
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else year % 4 != 0:
print('Year is not divisible by 4')
(1 point)
Responses
There should not be a colon after the function definition.
There should not be a colon after the function definition.
The print statements shall be ended with a semi-colon.
The print statements shall be ended with a semi-colon.
You cannot add a conditional statement after the else keyword.
You cannot add a conditional statement after the else keyword.
There should be a double modulus to check for the remainder.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The error in the syntax of the provided code is:
**You cannot add a conditional statement after the else keyword.**
In Python, the `else` statement does not take a condition; it should simply be followed by a colon and the block of code to execute if the `if` condition is not met. The correct syntax should be:
```python
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else:
print('Year is not divisible by 4')
```
**You cannot add a conditional statement after the else keyword.**
In Python, the `else` statement does not take a condition; it should simply be followed by a colon and the block of code to execute if the `if` condition is not met. The correct syntax should be:
```python
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else:
print('Year is not divisible by 4')
```
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