Question

Identify the error in the syntax of the following code: def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else year % 4 != 0: print('Year is not divisible by 4') (1 point) Responses You cannot add a conditional statement after the else keyword. You cannot add a conditional statement after the else keyword. There should be a double modulus to check for the remainder. There should be a double modulus to check for the remainder. There should not be a colon after the function definition. There should not be a colon after the function definition. The print statements shall be ended with a semi-colon

Answer 1

How can we filter out numbers less than 2 in a number sequence to find prime numbers?(1 point) Responses Our code needs to throw an error if numbers less than 2 are given. Our code needs to throw an error if numbers less than 2 are given. We can have a predefined list of all prime numbers and check if the given number is inside that list. We can have a predefined list of all prime numbers and check if the given number is inside that list. We can test numbers less than 2 by checking if it is divisible by 2. We can test numbers less than 2 by checking if it is divisible by 2. We can have a conditional check to filter out numbers less than 2

Answer 2

Consider a list [a, b, c, d]. Which element exists at index 4?(1 point) Responses the element a the element a the element b the element b the element d the element d There exists no element at index 4

Answer 3

Which of the following is the method of list traversal?(1 point) Responses for loop for loop if-else if-else condition if-else if-else condition if condition if condition if-else condition

Answer 4

The correct identification of the error in the syntax of the code is:

**You cannot add a conditional statement after the else keyword.**

The "else" statement should not have a condition directly following it. Instead, it serves as a catch-all for the condition specified in the preceding "if" statement. To fix the code, it should simply use "else:" without a condition.

Here's the corrected code:

```python
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else:
print('Year is not divisible by 4')
```

Answer 5

The correct approach to filter out numbers less than 2 in a number sequence to find prime numbers is:

**We can have a conditional check to filter out numbers less than 2.**

Prime numbers are defined as natural numbers greater than 1 that are not divisible by any other numbers except for 1 and themselves. Therefore, checking whether a number is less than 2 allows us to exclude it from consideration as a prime number.

For example, the code could look something like this:

```python
def is_prime(n):
if n < 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return True
```

This function directly filters out numbers less than 2 and checks the remaining numbers for primality.

Answer 6

The correct response is:

**There exists no element at index 4.**

In Python, indexing starts at 0. For the list `[a, b, c, d]`, the indices of the elements are as follows:

- Index 0: a
- Index 1: b
- Index 2: c
- Index 3: d

Since the list contains only 4 elements, the available indices are 0 to 3. Therefore, there is no element at index 4, which would exceed the bounds of the list.

Answer 7

The correct response is:

**for loop**

The `for` loop is a common method used for traversing lists (and other iterable objects) in Python. It allows you to iterate over each element in the list one at a time.

For example, you can use a `for` loop to traverse a list like this:

```python
my_list = [1, 2, 3, 4]
for item in my_list:
print(item)
```

This code will print each element of `my_list`.