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Solve the equation −(x−3)2−3=7 and re-express the answer as a complex number in the standard form a±bi .(1 point)Asked by hudson
Solve the equation −(x−3)2−3=7
and re-express the answer as a complex number in the standard form a±bi
.(1 point)
and re-express the answer as a complex number in the standard form a±bi
.(1 point)
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Answered by
GPT-4o mini
To solve the equation \(- (x - 3)^2 - 3 = 7\), we can first isolate the squared term. Let's start by moving -3 to the other side:
\[
-(x - 3)^2 = 7 + 3
\]
This simplifies to:
\[
-(x - 3)^2 = 10
\]
Now, multiply both sides by -1:
\[
(x - 3)^2 = -10
\]
Next, we take the square root of both sides. Remember that the square root of a negative number involves the imaginary unit \(i\):
\[
x - 3 = \pm \sqrt{-10}
\]
This can be expressed as:
\[
x - 3 = \pm i \sqrt{10}
\]
Now, isolate \(x\):
\[
x = 3 \pm i \sqrt{10}
\]
Thus, we have two solutions:
\[
x = 3 + i\sqrt{10} \quad \text{and} \quad x = 3 - i\sqrt{10}
\]
In standard form \(a \pm bi\), the answer can be expressed as:
\[
\boxed{3 \pm i\sqrt{10}}
\]
\[
-(x - 3)^2 = 7 + 3
\]
This simplifies to:
\[
-(x - 3)^2 = 10
\]
Now, multiply both sides by -1:
\[
(x - 3)^2 = -10
\]
Next, we take the square root of both sides. Remember that the square root of a negative number involves the imaginary unit \(i\):
\[
x - 3 = \pm \sqrt{-10}
\]
This can be expressed as:
\[
x - 3 = \pm i \sqrt{10}
\]
Now, isolate \(x\):
\[
x = 3 \pm i \sqrt{10}
\]
Thus, we have two solutions:
\[
x = 3 + i\sqrt{10} \quad \text{and} \quad x = 3 - i\sqrt{10}
\]
In standard form \(a \pm bi\), the answer can be expressed as:
\[
\boxed{3 \pm i\sqrt{10}}
\]
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