Hi, the question is: Write the equation of the parabola with vertex(3,-1) and x-intercepts 2 and 4.

Question

I did this:
y=?(x-3)^2-1

How to find the a-value?

Many thanks, and I appreciate any answer!

Answer 1

y=a(x-3)^2-1

x-intercept 2 ----> the point (2,0) lies on it

0 = a(1) - 1
a = 1

y=(x-3)^2-1