A shaft which rotates at 300r/min is uniformly accelerated to 600r/min in 15secs.Calculate:

Question

(a) The angular acceleration.
(b) The angle through which the shaft has turned during the acceleration.

Answer 1

angular acceleration= change in ang velociyt/time= 300rev/min/.25min=1200rev/min^2

you may want to change the units.

displcement= wi*t+1/2 angacc*time^2=
=300rev/min*.25min+ 1/2*1200rev/min^2*(1/4 min)^2