Asked by Ishola
A shaft which rotates at 300r/min is uniformly accelerated to 600r/min in 15secs.Calculate:
(a) The angular acceleration.
(b) The angle through which the shaft has turned during the acceleration.
(a) The angular acceleration.
(b) The angle through which the shaft has turned during the acceleration.
Answers
Answered by
bobpursley
angular acceleration= change in ang velociyt/time= 300rev/min/.25min=1200rev/min^2
you may want to change the units.
displcement= wi*t+1/2 angacc*time^2=
=300rev/min*.25min+ 1/2*1200rev/min^2*(1/4 min)^2
you may want to change the units.
displcement= wi*t+1/2 angacc*time^2=
=300rev/min*.25min+ 1/2*1200rev/min^2*(1/4 min)^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.