a shaft rotation @ 800 rpm delivers a torque of 240 N.m to an output shaft that is rotating @ 200 rpm.

Question

a shaft rotation @ 800 rpm delivers a torque of 240 N.m to an output shaft that is rotating @ 200 rpm. 
a. if the efficiency of the machine is 70%, compute the output torque
b, what is the output power

e=Po/Pi   .7=x/240 N.m   = 168 N.m

this is not the answer in the book so I obviously have no idea what I am doing...help?

bobpursley · Answer

.7=Torque*200/240*600 torque out=.7*3*240