Asked by Jeannine
a shaft rotation @ 800 rpm delivers a torque of 240 N.m to an output shaft that is rotating @ 200 rpm.
a. if the efficiency of the machine is 70%, compute the output torque
b, what is the output power
e=Po/Pi .7=x/240 N.m = 168 N.m
this is not the answer in the book so I obviously have no idea what I am doing...help?
a. if the efficiency of the machine is 70%, compute the output torque
b, what is the output power
e=Po/Pi .7=x/240 N.m = 168 N.m
this is not the answer in the book so I obviously have no idea what I am doing...help?
Answers
Answered by
bobpursley
.7=Torque*200/240*600
torque out=.7*3*240
torque out=.7*3*240
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