Write an equation in slope-intercept form for the graph shown.



A coordinate plane with a line passing through points (0, negative 2) and (4, negative 1)

1 answer

To write the equation of the line in slope-intercept form (y = mx + b), we first need to determine the slope (m) and the y-intercept (b).

  1. Calculate the slope (m): The formula for slope (m) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

    \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

    Using the points (0, -2) and (4, -1):

    • \( (x_1, y_1) = (0, -2) \)
    • \( (x_2, y_2) = (4, -1) \)

    So the slope is:

    \[ m = \frac{-1 - (-2)}{4 - 0} = \frac{-1 + 2}{4} = \frac{1}{4} \]

  2. Identify the y-intercept (b): The y-intercept is the point where the line crosses the y-axis. From the given point (0, -2), we can see that:

    \[ b = -2 \]

  3. Write the equation in slope-intercept form: Now that we have the slope (m = \(\frac{1}{4}\)) and the y-intercept (b = -2), we can write the equation:

    \[ y = \frac{1}{4}x - 2 \]

Thus, the equation of the line in slope-intercept form is:

\[ y = \frac{1}{4}x - 2 \]

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