Write an equation in slope-intercept form for the graph shown.



A coordinate plane with a line passing through points (0, 2) and (1, negative 1)

1 answer

To write the equation of the line in slope-intercept form (y = mx + b), we need to determine the slope (m) and the y-intercept (b).

  1. Identify the points:

    • The line passes through the points (0, 2) and (1, -1).
  2. Calculate the slope (m): The slope formula is: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Using the points (0, 2) and (1, -1): \[ m = \frac{-1 - 2}{1 - 0} = \frac{-3}{1} = -3 \]

  3. Identify the y-intercept (b): The y-intercept is the value of y when x = 0. From the point (0, 2), we see that: \[ b = 2 \]

  4. Write the equation: Now that we have the slope and the y-intercept, we can write the equation of the line: \[ y = -3x + 2 \]

Thus, the equation in slope-intercept form for the line is: \[ \boxed{y = -3x + 2} \]

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