Question

arlene read 30 pages that is 10 more 10 more pages than half the pages Taylor read how many pages did Taylor Reed write an equation from the form PX + 2 equals R to represent the problem

Answer 1

Let's break down the information given in the problem.

We know that:
- Arlene read 30 pages.
- This amount is 10 more than half the pages that Taylor read.

Let's define the variable:
- Let \( T \) be the number of pages Taylor read.

According to the problem statement, we can formulate the following equation based on what we know:

\[ 30 = \frac{1}{2}T + 10 \]

Now, we want to rewrite it in the form \( PX + 2 = R \). To do this, we can adjust the equation a bit.

1. Subtract 10 from both sides:
\[
30 - 10 = \frac{1}{2}T
\]
\[
20 = \frac{1}{2}T
\]

2. Multiply both sides by 2 to eliminate the fraction:
\[
2 \cdot 20 = T
\]
\[
40 = T
\]

So, Taylor read 40 pages.

Now let's express the equation in the desired format \( PX + 2 = R \). We can rearrange the equation to fit this format.

Starting from:
\[ 20 = \frac{1}{2}T \]

We can rewrite it as:
\[ 20 - 2 = \frac{1}{2}T \]

Thus, if we let \( P = \frac{1}{2} \), \( X = T \), \( 2 = 2 \), and \( R = 20 \), we can rewrite our equation in the form:

\[
\frac{1}{2}T - 2 = 20 - 2
\]

This doesn't seem to match exactly, so we can express it as:

\[
0.5T - 2 = 20
\]

In conclusion, from the information provided, the answer is:
Taylor read 40 pages, and the equation can be represented in a form close to \( PX + 2 = R \):

\[
0.5T - 2 = 20
\]

Where \( P = 0.5 \), \( X = T \), and \( R = 20 \).