Identify the vertex of y=3(x−4)2−5 (2 points)

Answer 1

The given equation is in vertex form, which is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In the equation \( y = 3(x - 4)^2 - 5 \):

• \( a = 3 \) (indicating the parabola opens upwards)
• \( h = 4 \)
• \( k = -5 \)

Thus, the vertex of the given parabola is at the point \((4, -5)\).