Question

Identify the vertex of y=−10(x+15)^2−18
.(1 point)
Responses
-150, -18
-15,-18



(−10,−15)

(15,−18)

Answer 1

To find the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we can identify it directly from the vertex form of a quadratic equation, which is given by \( y = a(x - h)^2 + k \), where the vertex is \((h, k)\).

In this case:

- The function is in the form \( y = -10(x - (-15))^2 - 18 \).
- Here, \( h = -15 \) and \( k = -18 \).

Therefore, the vertex of the function is \((-15, -18)\).

So, the correct response is:

**-15, -18**.