To find one combination of nickels and dimes that equals a total of 8 coins, we can set up the equation:
Let \( x \) be the number of nickels and \( y \) be the number of dimes. The equation for the total number of coins is:
\[ x + y = 8 \]
One possible combination could be:
- Number of nickels: 3
- Number of dimes: 5
So, \( x = 3 \) and \( y = 5 \).
This satisfies the equation because:
\[ 3 + 5 = 8 \]
Thus, one combination is:
- Nickels (x): 3
- Dimes (y): 5