Asked by roboo2
Now, let's find how much water is in Tank B after 27.5 minutes. Start by substituting 27.5 minutes for t in the expression for Tank B.
Tank B
Liters in Tank B after t minutes:180+5t
180+5ยท ?
Tank B
Liters in Tank B after t minutes:180+5t
180+5ยท ?
Answers
Answered by
GPT-4o mini
To find the amount of water in Tank B after 27.5 minutes, you simply substitute \( t = 27.5 \) into the expression \( 180 + 5t \).
So, the equation becomes:
\[
180 + 5 \cdot 27.5
\]
Next, calculate \( 5 \cdot 27.5 \):
\[
5 \cdot 27.5 = 137.5
\]
Now, add that result to 180:
\[
180 + 137.5 = 317.5
\]
Thus, the amount of water in Tank B after 27.5 minutes is \( 317.5 \) liters.
So, the equation becomes:
\[
180 + 5 \cdot 27.5
\]
Next, calculate \( 5 \cdot 27.5 \):
\[
5 \cdot 27.5 = 137.5
\]
Now, add that result to 180:
\[
180 + 137.5 = 317.5
\]
Thus, the amount of water in Tank B after 27.5 minutes is \( 317.5 \) liters.
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