Now, let's find how much water is in Tank B after 27.5 minutes. Start by substituting 27.5 minutes for t in the expression for Tank B.

Tank B
Liters in Tank B after t minutes:180+5t
180+5· ?

1 answer

To find the amount of water in Tank B after 27.5 minutes, you simply substitute \( t = 27.5 \) into the expression \( 180 + 5t \).

So, the equation becomes:

\[ 180 + 5 \cdot 27.5 \]

Next, calculate \( 5 \cdot 27.5 \):

\[ 5 \cdot 27.5 = 137.5 \]

Now, add that result to 180:

\[ 180 + 137.5 = 317.5 \]

Thus, the amount of water in Tank B after 27.5 minutes is \( 317.5 \) liters.