Asked by roboo2
We can distribute the 2 to rewrite the left side of the equation without parentheses. You can think of this as (2·4x)+(2·5). Rewrite the left side.
2(4x+5) = 10x+2
? + ? = 10x+2
2(4x+5) = 10x+2
? + ? = 10x+2
Answers
Answered by
GPT-4o mini
To rewrite the left side of the equation \(2(4x + 5)\) without parentheses, you can distribute the 2:
\[
2(4x + 5) = 2 \cdot 4x + 2 \cdot 5
\]
Calculating each term gives:
\[
2 \cdot 4x = 8x \quad \text{and} \quad 2 \cdot 5 = 10
\]
So, we have:
\[
2(4x + 5) = 8x + 10
\]
Now, we can equate \(8x + 10\) to \(10x + 2\):
\[
8x + 10 = 10x + 2
\]
This implies that:
\[
? + ? = 10x + 2 \quad \text{is} \quad 8x + 10
\]
Thus, you can write:
\[
8x + 10 = 10x + 2
\]
So, we can say that:
\[
8x + 10 \, \text{corresponds to} \, ? + ? = 10x + 2.
\]
In summary, you have \(8x\) and \(10\) as the components.
\[
2(4x + 5) = 2 \cdot 4x + 2 \cdot 5
\]
Calculating each term gives:
\[
2 \cdot 4x = 8x \quad \text{and} \quad 2 \cdot 5 = 10
\]
So, we have:
\[
2(4x + 5) = 8x + 10
\]
Now, we can equate \(8x + 10\) to \(10x + 2\):
\[
8x + 10 = 10x + 2
\]
This implies that:
\[
? + ? = 10x + 2 \quad \text{is} \quad 8x + 10
\]
Thus, you can write:
\[
8x + 10 = 10x + 2
\]
So, we can say that:
\[
8x + 10 \, \text{corresponds to} \, ? + ? = 10x + 2.
\]
In summary, you have \(8x\) and \(10\) as the components.
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