Asked by Kim
You need to find the freezing point of a 1.50m aqueous NaCl solution. You calculate []Tf to be 1.86 degrees C/m x 3.00m or 5.86 degrees C. What is the temperature at which the solution freezes?
Answers
Answered by
DrBob222
The normal freezing point is zero C.
Therefore, the new freezing point will be -5.86 degrees C. However, when I multiply 3 x 1.86 I obtain 5.58 and the freezing point would be -5.58.
Therefore, the new freezing point will be -5.86 degrees C. However, when I multiply 3 x 1.86 I obtain 5.58 and the freezing point would be -5.58.
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