Question
Ray is making a parfait by mixing honey and yogurt in the ration of 2 to 13. How much yogurt and honey does he need to make 600 grams of the parfait?
Answers
Answered by
GPT-4o mini
To solve the problem, we first need to understand the ratio of honey to yogurt, which is given as 2 to 13. This means for every 2 parts of honey, there are 13 parts of yogurt.
First, we add the parts of honey and yogurt together:
\[
2 \text{ (honey)} + 13 \text{ (yogurt)} = 15 \text{ parts total}
\]
Next, we need to determine how much each part weighs, given that the total weight of the parfait is 600 grams:
\[
\text{Weight of one part} = \frac{600 \text{ grams}}{15 \text{ parts}} = 40 \text{ grams per part}
\]
Now, we can find out how much honey and yogurt Ray needs:
1. **For Honey**:
- Honey weight = \(2 \text{ parts} \times 40 \text{ grams per part} = 80 \text{ grams}\)
2. **For Yogurt**:
- Yogurt weight = \(13 \text{ parts} \times 40 \text{ grams per part} = 520 \text{ grams}\)
Thus, Ray needs:
- **80 grams of honey**
- **520 grams of yogurt**
In conclusion, to make 600 grams of the parfait with the specified ratio, Ray needs 80 grams of honey and 520 grams of yogurt.
First, we add the parts of honey and yogurt together:
\[
2 \text{ (honey)} + 13 \text{ (yogurt)} = 15 \text{ parts total}
\]
Next, we need to determine how much each part weighs, given that the total weight of the parfait is 600 grams:
\[
\text{Weight of one part} = \frac{600 \text{ grams}}{15 \text{ parts}} = 40 \text{ grams per part}
\]
Now, we can find out how much honey and yogurt Ray needs:
1. **For Honey**:
- Honey weight = \(2 \text{ parts} \times 40 \text{ grams per part} = 80 \text{ grams}\)
2. **For Yogurt**:
- Yogurt weight = \(13 \text{ parts} \times 40 \text{ grams per part} = 520 \text{ grams}\)
Thus, Ray needs:
- **80 grams of honey**
- **520 grams of yogurt**
In conclusion, to make 600 grams of the parfait with the specified ratio, Ray needs 80 grams of honey and 520 grams of yogurt.