To calculate the relative formula mass (also known as molar mass) of lithium fluoride (LiF), we need to sum the atomic masses of lithium (Li) and fluorine (F).
- The atomic mass of lithium (Li) is approximately 6.94 g/mol.
- The atomic mass of fluorine (F) is approximately 19.00 g/mol.
Now we can calculate the relative formula mass of LiF:
\[ \text{Relative formula mass of LiF} = \text{atomic mass of Li} + \text{atomic mass of F} \] \[ \text{Relative formula mass of LiF} = 6.94 , \text{g/mol} + 19.00 , \text{g/mol} = 25.94 , \text{g/mol} \]
Therefore, the relative formula mass of lithium fluoride (LiF) is approximately 25.94 g/mol.