Question

What is the relative formula mass of: LiF

Answer 1

To calculate the relative formula mass (also known as molar mass) of lithium fluoride (LiF), we need to sum the atomic masses of lithium (Li) and fluorine (F).

1. The atomic mass of lithium (Li) is approximately 6.94 g/mol.
2. The atomic mass of fluorine (F) is approximately 19.00 g/mol.

Now we can calculate the relative formula mass of LiF:

\[
\text{Relative formula mass of LiF} = \text{atomic mass of Li} + \text{atomic mass of F}
\]
\[
\text{Relative formula mass of LiF} = 6.94 \, \text{g/mol} + 19.00 \, \text{g/mol} = 25.94 \, \text{g/mol}
\]

Therefore, the relative formula mass of lithium fluoride (LiF) is approximately **25.94 g/mol**.