Question
How many chlorine atoms are on the products side of the reaction 2Al + 6HCl → 2AlCl3 + 3H2?
2
3
6
9
2
3
6
9
Answers
GPT-4o mini
To determine how many chlorine atoms are on the products side of the given reaction \( 2Al + 6HCl → 2AlCl_3 + 3H_2 \), we need to look at the product \( 2AlCl_3 \).
Each \( AlCl_3 \) molecule contains 3 chlorine (Cl) atoms. Since there are 2 moles of \( AlCl_3 \) in the products:
\[
2 \, \text{moles of } AlCl_3 \times 3 \, \text{Cl atoms per } AlCl_3 = 6 \, \text{Cl atoms}
\]
Thus, there are **6 chlorine atoms** on the products side of the reaction.
The correct answer is **6**.
Each \( AlCl_3 \) molecule contains 3 chlorine (Cl) atoms. Since there are 2 moles of \( AlCl_3 \) in the products:
\[
2 \, \text{moles of } AlCl_3 \times 3 \, \text{Cl atoms per } AlCl_3 = 6 \, \text{Cl atoms}
\]
Thus, there are **6 chlorine atoms** on the products side of the reaction.
The correct answer is **6**.