Question

For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?

reactants: 1; products: 1
reactants: 1; products: 2
reactants: 2; products: 1
reactants: 2; products: 2

Answer 1

To analyze the equation \( \text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaCl} \):

On the **reactants side**:
- From \( \text{BaCl}_2 \), there are 2 chlorine atoms.

On the **products side**:
- From \( 2\text{NaCl} \), there are also 2 chlorine atoms.

Thus, the count of chlorine atoms is:
- Reactants: 2
- Products: 2

The correct choice is:
**reactants: 2; products: 2**.