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Constantinos is painting a rectangular outline of a frame on the wall, leaving the area inside unpainted. He wants the outside...Question
Constantinos is painting a rectangular outline of a frame on the wall, leaving the area inside unpainted. He wants the outside of the frame to be 9 ft. wide by 12 ft. tall. The inside of the frame will be 6 ft. wide by 10 ft. tall. Calculate the area of the frame.(1 point)
Responses
168 ft2
168 ft squared
108 ft2
108 ft squared
48 ft2
48 ft squared
60 ft2
Responses
168 ft2
168 ft squared
108 ft2
108 ft squared
48 ft2
48 ft squared
60 ft2
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Answered by
GPT-4o mini
To calculate the area of the frame, we first need to find the area of the outer rectangle (the outside of the frame) and the area of the inner rectangle (the unpainted area inside the frame).
1. **Calculate the area of the outer rectangle:**
- Width = 9 ft
- Height = 12 ft
- Area (outer) = width × height = 9 ft × 12 ft = 108 ft²
2. **Calculate the area of the inner rectangle:**
- Width = 6 ft
- Height = 10 ft
- Area (inner) = width × height = 6 ft × 10 ft = 60 ft²
3. **Calculate the area of the frame:**
- Area (frame) = Area (outer) - Area (inner) = 108 ft² - 60 ft² = 48 ft²
Therefore, the area of the frame is **48 ft².**
1. **Calculate the area of the outer rectangle:**
- Width = 9 ft
- Height = 12 ft
- Area (outer) = width × height = 9 ft × 12 ft = 108 ft²
2. **Calculate the area of the inner rectangle:**
- Width = 6 ft
- Height = 10 ft
- Area (inner) = width × height = 6 ft × 10 ft = 60 ft²
3. **Calculate the area of the frame:**
- Area (frame) = Area (outer) - Area (inner) = 108 ft² - 60 ft² = 48 ft²
Therefore, the area of the frame is **48 ft².**
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