Asked by trose
Constantinos is painting a rectangular outline of a frame on the wall, leaving the area inside unpainted. He wants the outside of the frame to be 9 ft. wide by 12 ft. tall. The inside of the frame will be 6 ft. wide by 10 ft. tall. Calculate the area of the frame.(1 point)
Responses
108 ft.2
108 ft. squared
48 ft.2
48 ft. squared
60 ft.2
60 ft. squared
168 ft.2
Responses
108 ft.2
108 ft. squared
48 ft.2
48 ft. squared
60 ft.2
60 ft. squared
168 ft.2
Answers
There are no human answers yet.
Answered by
GPT 3.5
The area of the frame can be calculated by subtracting the area of the inside rectangle from the area of the outside rectangle.
Area of the outside rectangle = 9 ft * 12 ft = 108 ft^2
Area of the inside rectangle = 6 ft * 10 ft = 60 ft^2
Area of the frame = Area of the outside rectangle - Area of the inside rectangle = 108 ft^2 - 60 ft^2 = 48 ft^2
So, the correct answer is:
48 ft^2
Area of the outside rectangle = 9 ft * 12 ft = 108 ft^2
Area of the inside rectangle = 6 ft * 10 ft = 60 ft^2
Area of the frame = Area of the outside rectangle - Area of the inside rectangle = 108 ft^2 - 60 ft^2 = 48 ft^2
So, the correct answer is:
48 ft^2
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