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Quadratic Functions from Situations Quick Check 2 of 52 of 5 Items Question While hiking, Marek throws a rock off a cliff that...Question
Quadratic Functions from Situations Quick Check
2 of 52 of 5 Items
Question
While hiking, Marek throws a rock off a cliff that is roughly 10 meters above a lake. This situation is modeled by the equation h=−4.9t2+10
, with h representing the height in meters and t the time in seconds. If you were to set up a table to determine when the rock hits the water, what would be a reasonable scale for the range?(1 point)
Responses
2
2
10
10
5
5
110
1 tenth
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                    Answered by
            GPT-4o mini
            
    To determine when the rock hits the water, we need to find when the height \( h \) is equal to 0 (when it reaches the lake). The equation given is:
\[ h = -4.9t^2 + 10 \]
To find when the rock hits the water, we can set \( h = 0 \):
\[ 0 = -4.9t^2 + 10 \]
This can be rearranged to find \( t \):
\[ 4.9t^2 = 10 \]
\[ t^2 = \frac{10}{4.9} \]
\[ t^2 \approx 2.04 \]
Taking the square root of both sides:
\[ t \approx \sqrt{2.04} \approx 1.43 \text{ seconds} \]
Now, when setting up a table to determine when the rock hits the water, we should consider a reasonable time scale for \( t \), such as increments of seconds leading up to about 1.5 seconds.
Looking at the provided response options for the range:
- 2
- 10
- 5
- 110
- 1 tenth
A reasonable scale for the range would be **2**, as it allows you to set up a table with entries like \( 0, 1, 2 \), which comfortably includes the time it takes for the rock to hit the water (approximately 1.43 seconds).
    
\[ h = -4.9t^2 + 10 \]
To find when the rock hits the water, we can set \( h = 0 \):
\[ 0 = -4.9t^2 + 10 \]
This can be rearranged to find \( t \):
\[ 4.9t^2 = 10 \]
\[ t^2 = \frac{10}{4.9} \]
\[ t^2 \approx 2.04 \]
Taking the square root of both sides:
\[ t \approx \sqrt{2.04} \approx 1.43 \text{ seconds} \]
Now, when setting up a table to determine when the rock hits the water, we should consider a reasonable time scale for \( t \), such as increments of seconds leading up to about 1.5 seconds.
Looking at the provided response options for the range:
- 2
- 10
- 5
- 110
- 1 tenth
A reasonable scale for the range would be **2**, as it allows you to set up a table with entries like \( 0, 1, 2 \), which comfortably includes the time it takes for the rock to hit the water (approximately 1.43 seconds).
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