function1 is a parabola with a vertex of (-1,-3) so its minimum is -3
since function2 shows a minimum value of 0
the first statement is true
min value of -3 at the point (-1,-3).
wo quadratic functions are shown.
Function 1:
f(x) = 4x2 + 8x + 1
Function 2:
x -2 -1 0 1
g(x) 2 0 2 8
Which function has the least minimum value and what are its coordinates?
Function 1 has the least minimum value and its coordinates are (−1, −3).
Function 1 has the least minimum value and its coordinates are (0, 1).
Function 2 has the least minimum value and its coordinates are (−1, 0).
Function 2 has the least minimum value and its coordinates are (0, 2).
2 answers
the minimum of function 2 is 0 at (-1,0)
for the first function 1
y = 4 x^2 + 8 x + 1
4 x^2 + 8 x = y - 1
x^2 + 2 x = (1/4) y - 1/4
x^2 + 2 x + 1 = (1/4)y + 3/4
(x+1)^1 = (1/4) (y+3)
so vertex at (-1, -3)
SO A
for the first function 1
y = 4 x^2 + 8 x + 1
4 x^2 + 8 x = y - 1
x^2 + 2 x = (1/4) y - 1/4
x^2 + 2 x + 1 = (1/4)y + 3/4
(x+1)^1 = (1/4) (y+3)
so vertex at (-1, -3)
SO A
1 answer