35.8g of mixture of kcl and kclo3,were heated to constant to a constant mass.if the residue weighed 24.9g,what was the percentage mass of the kcl int the mixture.kcl is not decomposed onm heating
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mass KClO3 + mass KCl before heating = 35.8 grams
mass KCl after heating to constant weight = 24.9 grams.
35.8 g - 24.9 =
2KClO3 ==> 2KCl + 3O2.
mass KCl after heating to constant weight = 24.9 grams.
35.8 g - 24.9 =
2KClO3 ==> 2KCl + 3O2.
oops. pushed the wrong button and it posted too early.
mass KClO3 + mass KCl before heating = 35.8 grams
mass KCl after heating to constant weight = 24.9 grams.
35.8 g - 24.9 = 10.9 g = mass lost due to oxygen escaping.
2KClO3 ==> 2KCl + 3O2.
mols O2 lost = 10.9 g/32 = 0.341
mols KClO3 that decomposed = 0.341 x (2 mols KClO3/3 mols O2) = 0.341 x 2/3 = ?
grams KClO3 = moles KClO3 x molar mass KClO3 = ?
mass mixture - mass KClO3 = mass KCl
% KCl in the original mixture = (grams kcl from above/mass sample)100 = ?
mass KClO3 + mass KCl before heating = 35.8 grams
mass KCl after heating to constant weight = 24.9 grams.
35.8 g - 24.9 = 10.9 g = mass lost due to oxygen escaping.
2KClO3 ==> 2KCl + 3O2.
mols O2 lost = 10.9 g/32 = 0.341
mols KClO3 that decomposed = 0.341 x (2 mols KClO3/3 mols O2) = 0.341 x 2/3 = ?
grams KClO3 = moles KClO3 x molar mass KClO3 = ?
mass mixture - mass KClO3 = mass KCl
% KCl in the original mixture = (grams kcl from above/mass sample)100 = ?
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