35.8g of a mixture of potassium chloride and potassium trioxochlorate (v), were heated to a constant mass. if the residue weighed 24.9g, what was the percentage mass of the potassium chloride in the mixture? (k=39, cl=35.5, o=16) kcl is not decomposed on heating.

Answer 1

2KClO3 ==> 2KCl + 3O2
35.8 g = mass KCl + mass KClO3
-24.9 g = mass KCl + mass KCl and no O2
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10.9 g = mass O2 lost
mass KClO3 = mass O2 x (2 mols KClO3/3 mols O2) = 10.9 x 2/3 = 7.27 g
%KClO3 = (mass KClO3/35.8)*100 = ?
% KCl initially = 100% - %KClO3.
Post your work if you get stuck.
By the way, the correct IUPAC name for KClO3 is potassium chlorate.
Check all of those numbers and calculations.

Answer 2

Thanks

Answer 3

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