Asked by Zuzu
alim purchased a motorcycle and it depreciates each year. Its depreciation is represented by the function f(x) = 14000(1−0.09)x When will the motorcycle be worth $7000?
Answers
Answered by
GPT-4o mini
To find out when the motorcycle will be worth $7000, we need to set the given depreciation function equal to $7000 and solve for \( x \):
\[
f(x) = 14000(1 - 0.09)^x
\]
Setting this equal to $7000:
\[
14000(1 - 0.09)^x = 7000
\]
Next, divide both sides by 14000:
\[
(1 - 0.09)^x = \frac{7000}{14000}
\]
This simplifies to:
\[
(1 - 0.09)^x = 0.5
\]
Substituting \( 1 - 0.09 \) with \( 0.91 \):
\[
0.91^x = 0.5
\]
To solve for \( x \), we can take the logarithm of both sides. Using the natural logarithm:
\[
\ln(0.91^x) = \ln(0.5)
\]
Using the power rule of logarithms:
\[
x \cdot \ln(0.91) = \ln(0.5)
\]
Now, solve for \( x \):
\[
x = \frac{\ln(0.5)}{\ln(0.91)}
\]
Calculating the values:
- \( \ln(0.5) \approx -0.6931 \)
- \( \ln(0.91) \approx -0.0943 \)
So,
\[
x \approx \frac{-0.6931}{-0.0943} \approx 7.35
\]
Since \( x \) represents years, we round to the nearest whole number. This means the motorcycle will be worth approximately $7000 after about **7 years**.
\[
f(x) = 14000(1 - 0.09)^x
\]
Setting this equal to $7000:
\[
14000(1 - 0.09)^x = 7000
\]
Next, divide both sides by 14000:
\[
(1 - 0.09)^x = \frac{7000}{14000}
\]
This simplifies to:
\[
(1 - 0.09)^x = 0.5
\]
Substituting \( 1 - 0.09 \) with \( 0.91 \):
\[
0.91^x = 0.5
\]
To solve for \( x \), we can take the logarithm of both sides. Using the natural logarithm:
\[
\ln(0.91^x) = \ln(0.5)
\]
Using the power rule of logarithms:
\[
x \cdot \ln(0.91) = \ln(0.5)
\]
Now, solve for \( x \):
\[
x = \frac{\ln(0.5)}{\ln(0.91)}
\]
Calculating the values:
- \( \ln(0.5) \approx -0.6931 \)
- \( \ln(0.91) \approx -0.0943 \)
So,
\[
x \approx \frac{-0.6931}{-0.0943} \approx 7.35
\]
Since \( x \) represents years, we round to the nearest whole number. This means the motorcycle will be worth approximately $7000 after about **7 years**.