Question
Salim purchased a motorcycle and it depreciates each year. Its depreciation is represented by the function f(x) = 14000(1−0.09)x
When will the motorcycle be worth $7000?
Desmos Link
(1 point)
Responses
6.7 years
6.7 years
7 years
7 years
7.3 years
7.3 years
8 years
When will the motorcycle be worth $7000?
Desmos Link
(1 point)
Responses
6.7 years
6.7 years
7 years
7 years
7.3 years
7.3 years
8 years
Answers
Answered by
GPT-4o mini
To determine when the motorcycle will be worth $7000, we will set the depreciation function equal to $7000:
\[
f(x) = 14000(1 - 0.09)^x = 7000
\]
This simplifies to:
\[
14000(0.91)^x = 7000
\]
Next, we can divide both sides by 14000:
\[
(0.91)^x = \frac{7000}{14000} = 0.5
\]
Now, we will take the logarithm of both sides to solve for \(x\):
\[
\log((0.91)^x) = \log(0.5)
\]
Using the power rule of logarithms:
\[
x \log(0.91) = \log(0.5)
\]
Now, solving for \(x\):
\[
x = \frac{\log(0.5)}{\log(0.91)}
\]
Using a calculator to find the values of the logarithms:
\[
\log(0.5) \approx -0.3010
\]
\[
\log(0.91) \approx -0.0434
\]
Now we can substitute these values into the equation:
\[
x = \frac{-0.3010}{-0.0434} \approx 6.93
\]
Rounding to one decimal place, we find that \(x \approx 6.9\) years.
Given the options, the motorcycle will be worth $7000 in approximately **7 years**.
\[
f(x) = 14000(1 - 0.09)^x = 7000
\]
This simplifies to:
\[
14000(0.91)^x = 7000
\]
Next, we can divide both sides by 14000:
\[
(0.91)^x = \frac{7000}{14000} = 0.5
\]
Now, we will take the logarithm of both sides to solve for \(x\):
\[
\log((0.91)^x) = \log(0.5)
\]
Using the power rule of logarithms:
\[
x \log(0.91) = \log(0.5)
\]
Now, solving for \(x\):
\[
x = \frac{\log(0.5)}{\log(0.91)}
\]
Using a calculator to find the values of the logarithms:
\[
\log(0.5) \approx -0.3010
\]
\[
\log(0.91) \approx -0.0434
\]
Now we can substitute these values into the equation:
\[
x = \frac{-0.3010}{-0.0434} \approx 6.93
\]
Rounding to one decimal place, we find that \(x \approx 6.9\) years.
Given the options, the motorcycle will be worth $7000 in approximately **7 years**.