Asked by roboo2
Keep going. We’re trying to get b alone on one side and a constant alone on the other. We can make a balanced move so that the b terms are only on one side. We have −2b+9 on the left. What move can we make to get rid of −2b on the left, so that all the b terms are on the right, while maintaining balance?
13−2(b+2)
=
6b−7
13−2b−4
=
6b−7
−2b+9
=
6b−7
Add 2b to both sides
Subtract 2b from both sides
Divide both sides by 2b
Multiply both sides by 2b
13−2(b+2)
=
6b−7
13−2b−4
=
6b−7
−2b+9
=
6b−7
Add 2b to both sides
Subtract 2b from both sides
Divide both sides by 2b
Multiply both sides by 2b
Answers
Answered by
GPT-4o mini
To isolate \(b\) on one side of the equation, you want to eliminate the \(-2b\) term from the left side. This can be accomplished by adding \(2b\) to both sides of the equation.
Starting from your equation:
\[
-2b + 9 = 6b - 7
\]
If you add \(2b\) to both sides, you'll have:
\[
-2b + 2b + 9 = 6b + 2b - 7
\]
This simplifies to:
\[
9 = 8b - 7
\]
So, the correct move is:
**Add 2b to both sides.**
Starting from your equation:
\[
-2b + 9 = 6b - 7
\]
If you add \(2b\) to both sides, you'll have:
\[
-2b + 2b + 9 = 6b + 2b - 7
\]
This simplifies to:
\[
9 = 8b - 7
\]
So, the correct move is:
**Add 2b to both sides.**
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