Asked by jessica

Determine the volume (in mL) of a 0.184 M CaCl2 solution that would be required to obtain 73.4 g of CaCl2.
Answered by DrBob222
0.184 x molar mass = grams CaCl2/L = 20.42 grams. So if you have 20.42 g in 1000 mL, how many mL will it take to obtain 73.4g.
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